**Bar Bending schedule **plays a vital role in finding the quantities of reinforcement in structure. In order to find out the Bar bending schedule for slab or steel reinforcement in Slab, I recommend you to learn Basics of** Bar Bending schedule** and how to adopt **concrete cover** for different components of a building.

**Bar Bending Schedule for Slab**

There are **16 different types of slabs** in construction. Well, the thickness of the slab generally varies between 4″ to 8″. We generally adopt 6″ (0.15m) slab thickness. For occasionally heavy loads we adopt 8″ and above thickness slabs.

**Quantity of Reinforcement (Steel) required for Slab Or Bar Bending Schedule for Slab**

In this post, I am finding out the Estimation of Steel reinforcement required for a Slab to work on this I considered a plan as shown below.

Primarily slabs are classified into two types **One-way Slab and Two-way slab** to know more about the differences refer here.

In one-way slab, Main bars are provided in a shorter direction (Cranked bars) and distribution bars are provided in Longer direction (Straight bars). Whereas in Two-way slab Main bars (cranked bars) are provided in both directions. Usually, the Two-way slab is adopted when the length and width of the slab are more than 4m.

Well to make you perfect in Bar Bending Schedule for a slab, I am considering a One-way slab and two-way slab as shown in the figure. Main bars and distribution bars are provided in the One-way slab. In two way slab, distribution bars are provided on both sides of the slab.

**Distribution bars:-** These bars are straight bars.

**Main bars:-** These bars are cranked bars. Main bars are cranked at an angle of **45 Degree with the length of 0.42D**

**Where, D = Depth of Slab- Top cover – Bottom cover**

Extra Bars:- The extra bar is provided at the bottom of Cranked bars to maintain the framework of the slab.

The length of the Extra bar is** L/4.**

**Steps to calculate the Reinforcement required for Slab**

1- Deduct the cover for finding the length of the bar.

2- Evaluate the length of the distribution bar

3- Calculate the Value of ‘D’ (Depth of the slab- Top cover- Bottom cover)

4- Find out the No. of Bars

5- Compute the Total wt of steel required for slab reinforcement.

**Consider,**

Dia of bars = 10mm , Spacing between bars = 0.10m , Depth of Slab = 0.15m

**Floor Slab – 1 (Two-Way Slab)**

**Bars along X-Axis**

**Bars along Y-Axis**

Total wt of Bars = 150.285+150.091 = **300.376Kgs **

**For Floor slab -2 (One-way slab) **

As per the above figure Floor slab, -2 is a One-way slab. In this kind of slab Mains bars (cranked bars) are provided in shorter direction hence there is no need of calculating the crank bar length in Y-direction (from fig). Evaluate the length of Bar as given in the figure by deducting the covering length. Whereas in X Direction Crank bar length is considered.